Which quantity contains the LEAST number of atoms?

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Which quantity contains the LEAST number of atoms?

$a .$ $a.$ $Two moles of NaOH;$ $"Two moles of NaOH;"$

$b .$ $b.$ $One mole of ammonia;$ $"One mole of ammonia; "$

$c .$ $c.$ $Two moles of calcium chloride;$ $"Two moles of calcium chloride; "$

$d .$ $d.$ $One mole of alumina.$ $"One mole of alumina. "$

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Answer 1 · 2017-08-02T09:07:01

I would go for $option b$ $"option b"$ .

Explanation:

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$a .$ $a.$ $Two moles of NaOH;$ $"Two moles of NaOH;"$ $2 \times N a^{+} + 2 H O^{-}$ $2xxNa^+ + 2HO^-$ $moles$ $"moles"$

$b .$ $b.$ $One mole of ammonium;$ $"One mole of ammonium; "$ $1 \times N H_{3} \cdot m o l$ $1xxNH_3*mol$

$c .$ $c.$ $Two moles of calcium chloride;$ $"Two moles of calcium chloride; "$ $2 \times C a^{2 +} + 4 \times C l^{-} \cdot m o l$ $2xxCa^(2+)+4xxCl^(-)*mol$

$d .$ $d.$ $One mole of alumina;$ $"One mole of alumina; "$ $2 \times A l^{3 +} + 3 \times O^{2 -} \cdot m o l$ $2xxAl^(3+)+3xxO^(2-)*mol$

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Which quantity contains the LEAST number of atoms?

$a .$ $a.$ $Two moles of NaOH;$ $"Two moles of NaOH;"$

$b .$ $b.$ $One mole of ammonia;$ $"One mole of ammonia; "$

$c .$ $c.$ $Two moles of calcium chloride;$ $"Two moles of calcium chloride; "$

$d .$ $d.$ $One mole of alumina.$ $"One mole of alumina. "$

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