Question #8b490

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Question #8b490

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Answer 1 · 2017-08-03T01:36:34

$\frac{3}{5} or 60 %$ $3/5 or 60%$

Explanation:

The probability of landing on any odd number is equal to the probability of each individual odd number added together.

As shown by the graph, the chance of pulling a $1, 3, or 5$ $1, 3, or 5$ from the bag is $\frac{3}{10}, \frac{1}{10}, and \frac{1}{5},$ $3/10, 1/10, and 1/5,$ respectively.

$\frac{3}{10} + \frac{1}{10} + \frac{1}{5}$ $3/10 + 1/10 + 1/5$

$= \frac{3}{5}$ $= 3/5$

$= 60 % .$ $= 60%.$

Answer 2 · 2017-08-03T08:00:15

$\frac{3}{5}$ $3/5$

Explanation:

Another method would be by excluding the choices we do NOT want.

The probability of an ODD means that we DO NOT WANT an even.

The probability of an even number $= P (2, 4)$ $= P(2,4)$

$P (EVEN) = \frac{1}{5} + \frac{1}{5} = \frac{2}{5}$ $P("EVEN") = 1/5+1/5 = 2/5$

$P (ODD) = 1 - P (EVEN)$ $P("ODD") = 1 -P("EVEN")$

$= 1 - \frac{2}{5} = \frac{3}{5}$ $= 1-2/5 = 3/5$

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Question #8b490

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