Question #4855b

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Answer 1 · 2017-08-14T22:48:07

The answer is B) 0.67 M.

Refer to the explanation for the process.

$Molarity (M) = \frac{moles of solute}{liters of solution}$ $"Molarity (M)"="moles of solute"/"liters of solution"$

The mol ${MgCl}_{2}$ $"MgCl"_2$ has been given as $0.50$ $0.50$ .

The volume of the solution is in milliliters (mL) and needs to be converted to liters (L).

$750cancel"mL"xx(1"L")/(1000cancel"mL")="0.75 L"$

Now you can calculate the molarity of the solution.

$"Molarity MgCl"_2=("0.50 mol MgCl"_2)/(0.75"L")="0.67 mol "/"L"="0.67 M"$