Question

Question #51efc

Answer 1

`"NHF"_2` has `color(red)(7)` lone pairs of electrons, `3` single bonds, and nitrogen has a usual octet. You seem to have counted the three single bonds as additional lone pairs.

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`"NHF"_2` is analogous to `"NH"_3`, with two hydrogen atoms replaced by fluorine atoms.

Three lone pairs per fluorine atom gives `6`, plus the lone pair on nitrogen gives `7`. `"N"` atom has the usual octet; two electrons from each single bond and two from the lone pair.