Question #00c6f

1 Answer
Ernest Z.
Aug 22, 2017

There are 1.1 g of "NH"_3NH3 in the solution.

Explanation:

Step 1. Calculate the moles of "NH"_3NH3

"Moles of NH"_3 = 0.085 color(red)(cancel(color(black)("L NH"_3))) × "0.75 mol NH"_3/(1 color(red)(cancel(color(black)("L NH"_3)))) = "0.0638 mol NH"_3

Step 2. Calculate the mass of "NH"_3

"Mass of NH"_3 = 0.0638 color(red)(cancel(color(black)("mol NH"_3))) × "17.03 g NH"_3/(1 color(red)(cancel(color(black)("mol NH"_3)))) = "1.1 g NH"_3

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