Question

We know that `K_w=10^(-14)` at `298*K`. How would `K_w` evolve at `373*K`?

Answer 1

Would you not expect it to be greater than `K_w` at `298*K`?

Explanation:

We know that at `298*K`,

`2H_2OrightleftharpoonsH_3O^+ + HO^-`, `K_w=10^-14=[H_3O^+][HO^-]`.

This site relates that `K_w=51.3xx10^-14` at `373*K`. Because this is manifestly a BOND-BREAKING reaction, we would expect that the given equilibrium LIES farther to the right. Does the given value support this expectation........?

What is `pH` at this temperature?

Answer 2

The link below gives you information on this.

Explanation:

http://chemguide.co.uk/physical/acidbaseeqia/kw.html