What is the "molarity" of a 35.67*g mass of calcium chloride dissolved in enough water to make a volume of 1.0*L?

1 Answer
anor277
Aug 24, 2017

We take the quotient, "Molarity"="Moles of solute"/"Volume of solution"

Explanation:

And thus........

((35.67*g)/(110.98*g*mol^-1))/(1.0*L)=0.321*mol*L^-1 with respect to "calcium chloride". What is the molar concentration with respect to chloride ion?

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