The pressure on a $22.5L$ volume of gas enclosed in a piston is REDUCED from $748mmHg$ to $725mm*Hg$ . What is the new volume?

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Answer 1 · 2017-08-27T13:09:26

Well, $P_1V_1=P_2V_2$ .......and the VOLUME should INCREASE BECAUSE YOU DECREASE the PRESSURE......

And so.... $V_2=(P_1V_1)/P_2$ , which clearly has the units of volume. Agreed?

$V_2=(22.5*Lxx748*mm*Hg)/(725*mm*Hg)=??*L$

The pressure on a 22.5*L22.5*L volume of gas enclosed in a piston is REDUCED from 748*mm*Hg748*mm*Hg to 725*mm*Hg725*mm*Hg. What is the new volume?