What is the concentration in $"ppm"$ if $18.5g$ of solute are dissolved in a $125L$ volume?

Question

4260 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-28T15:01:29

Well $1*"ppm"$ $=$ $1*mg*L^-1$ .......

And so we set up the quotient, $"milligrams of solute"/"litres of water"$

$=(18.5*gxx10^3*mg*g^-1)/(125000*gxx10^-3*L*g^-1)=148.0*"ppm"$

What is the concentration in "ppm""ppm" if 18.5*g18.5*g of solute are dissolved in a 125*L125*L volume?