If the molar mass of a material is $147.01gmol^-1$ , what mass of the material is required for a $1L$ volume of a $0.1mol*L^-1$ solution?

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Answer 1 · 2017-08-29T19:27:14

And we get a required mass of $14.7*g$ .

And thus $"moles"="volume"xx"concentration"$

We require..... $1*Lxx0.1*mol*L^-1=0.1*mol$ .

And now we simply multiply this molar quantity by the molar mass, i.e. $0.1*molxx147.01*g*mol^-1=14.7*g$ .....

If the molar mass of a material is 147.01*g*mol^-1147.01*g*mol^-1, what mass of the material is required for a 1*L1*L volume of a 0.1*mol*L^-10.1*mol*L^-1 solution?