What is the average atomic mass of titanium if we have an isotopic distribution of $78.5%$ of $""^46Ti$ , $45.95263"amu"$ , $12.3%$ of $""^48Ti$ , $47.94795"amu"$ , and $""^50Ti$ , $49.94479*"amu"$ ?

Question

9731 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-30T04:34:12

This is simply the WEIGHTED AVERAGE of the individual isotopes.....I gets approx. $46.6*"amu"$ .

$"Atomic mass of titanium"={0.785xx45.95263+0.123xx47.94795+0.092xx49.94479}*"amu"=??$

Is this the same as on this planet?

What is the average atomic mass of titanium if we have an isotopic distribution of 78.5%78.5% of ""^46Ti""^46Ti, 45.95263*"amu"45.95263*"amu", 12.3%12.3% of ""^48Ti""^48Ti, 47.94795*"amu"47.94795*"amu", and ""^50Ti""^50Ti, 49.94479*"amu"49.94479*"amu"?