What mass of carbon dioxide will result from the decomposition of $300*g$ of calcium carbonate?

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Answer 1 · 2017-09-01T18:12:27

Approx. $132*g$ of gas should be evolved.

We need a stoichiometric equation to represent the equation, and inform our calculation.....

$CaCO_3(s) + Delta rarrCaO(s) + CO_2(g)uarr$

And thus 1 equiv of calcium carbonate decomposes with heat to give 1 equiv of calcium oxide, and 1 equiv of carbon dioxide.

And so we determine the molar quantities......

$"Moles of calcium carbonate"=(300*g)/(100.09*g*mol^-1)=3.00*mol$

And thus we get THREE MOLES EACH of calcium oxide and carbon dioxide.......

$"Mass of CaO"=3*molxx56.08*g*mol^-1=??*g$

$"Mass of carbon dioxide"=3*molxx44.01*g*mol^-1=??*g$

What mass of carbon dioxide will result from the decomposition of 300*g300*g of calcium carbonate?