How would the volume if a gas in a piston under $14"bar"$ pressure with a volume of $312mL$ , were reduced in pressure to $7*"bar"$ pressure?

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Answer 1 · 2017-09-04T14:30:50

Would it not be around $7*"bar"$ .........?

Old Boyle's Law holds that given constant temperature, and for a given amount of gas..... $Pprop1/V$ ........

Else, $PV=k$ , and thus solving for $k$ at different pressures and volumes......

$P_1V_1=P_2V_2$

And so...... $P_2=(P_1V_1)/V_2=(14*"bar"xx312*mL)/(652*mL)=??*"bar"$ .

How would the volume if a gas in a piston under 14*"bar"14*"bar" pressure with a volume of 312*mL312*mL, were reduced in pressure to 7*"bar"7*"bar" pressure?