Question #ba64c

1 Answer
Sep 6, 2017

Let's underthink the problem....suppose you had "3 dozen" individual water molecules, i.e. 36 molecules......

Explanation:

Do you agree that in this scenario we gots 36 individual oxygen atoms, and 72 hydrogen atoms? Yea or nay?

The question here specified 3.4*mol water molecules, which has a mass of 3.4*molxx18.01*g*mol^-1=61.2*g of water......

But a mole is simply a numerical quantity....i.e. N_A=6.022xx10^23*mol^-1.

And so back to your problem, we gots....

3.4xxN_A "oxygen atoms" = 2.05xx10^24 "oxygen atoms".

And......

2xx3.4xxN_A "hydrogen atoms" = 4.09xx10^24 "hydrogen atoms".

And the moral, the mole is simply a number, admittedly a very large number.......with the property that a mole of "hydrogen atoms" has a mass of 1*g.