Question #6dadc

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Question #6dadc

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Answer 1 · 2017-09-10T03:40:08

The average atomic mass of the given sample of bromine is $80$ $80$ .

Explanation:

Since they both make up an abundance of $50 %$ $50%$ , just add $79$ $79$ and $81$ $81$ , then divide by $2$ $2$ .

$79 + 81 = 160$ $79+81=160$

$\frac{160}{2} = 80$ $160/2=80$

The following is probably what your teacher wants you to do. Multiply the given mass numbers by the decimal form for $50 %$ $50%$ , 0.50, and add them together.

$(0.50 \times 79) + (0.50 \times 81) =$ $(0.50xx79)+(0.50xx81)=$

$39.5 + 40.5 = 80$ $39.5+40.5=80$

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Question #6dadc

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