We gots ..................
18.9*"mile"^2-=18.9*"mile"^2xx2.59xx10^6*m^2*"mile"^-2"18.9⋅mile2≡18.9⋅mile2×2.59×106⋅m2⋅mile−2
=49.0xx10^6*m^2=49.0×106⋅m2 (i)(i)
And average depth is 47*ftxx0.3048*m*ft^-1=14.3*m47⋅ft×0.3048⋅m⋅ft−1=14.3⋅m (ii)(ii)
And "volume"=(i)xx(ii)=49.0xx10^6*m^2xx14.3*m=volume=(i)×(ii)=49.0×106⋅m2×14.3⋅m=
=702xx10^6*m^3=702×106⋅m3.
And we know that there are 10^3*L*m^-3103⋅L⋅m−3
And so we got 702xx10^6*m^3xx1000*L*m^-3-=702xx10^9*L702×106⋅m3×1000⋅L⋅m−3≡702×109⋅L.
An acquaintance of mine, an engineer, once started using "sydharbs"-=500000xx10^6*Lsydharbs≡500000×106⋅L as a measurement of LARGE volumes of water. A "sydharb"sydharb was the average volume of water in Sydney Harbour. This helped us vizualize the quantity, because we had all taken the ferry from Circular Quay to Manly across Sydney Harbour. How many "sydharbs"sydharbs have you got here?
