Question

Question #b6f4c

Answer 1

Approx. `10*mL`

Explanation:

With all these problems, the priority is to write a stoichiometrically balanced equation:

`H_2SO_4(aq) + 2NaOH(aq) rarr Na_2SO_4(aq) + 2H_2O(l)`

And thus ONE equiv of sulfuric acid reacts with TWO equiv of sodium hydroxide.

`"Moles of sodium hydroxide"=60.2*mLxx10^-3*L*mL^-1xx0.427*mol*L^-1=0.0257*mol`.

And thus `(0.0257*mol)/2` `H_2SO_4` are required.....

And so we take the quotient....

`((0.0257*mol)/2)/(1.28*mol*L^-1)xx10^3*mL*L^-1=10.0*mL`

Note that normally, when we do a titration we aim to use a volume of `15-20*mL` in order to minimize errors. Of course, you gots no choice when solving a problem.....