Question #b5e69

1 Answer
Sep 14, 2017

3.01 xx 10^21" molecules O"_23.01×1021 molecules O2

Explanation:

M_(CO_2) = "220 mg"MCO2=220 mg
MW_(CO_2) = "44.01 g/mol"MWCO2=44.01 g/mol
"O"_2 " molecules = ?"O2 molecules = ?

"moles " CO_2 = (M_(CO_2))/(MW_(CO_2)) = ("220 mg"/"1000 mg/g")/"44.01 g/mol" = "0.00500 mol"moles CO2=MCO2MWCO2=220 mg1000 mg/g44.01 g/mol=0.00500 mol

"moles O"_2 " per mole CO"_2 = 1moles O2 per mole CO2=1

"Avogadro's number" = N_A = 6.022 xx 10^23" molecules/mol"Avogadro's number=NA=6.022×1023 molecules/mol

"O"_2 " molecules" = "moles CO"_2 xx "moles O"_2 /"moles CO"_2 xx N_AO2 molecules=moles CO2×moles O2moles CO2×NA

= "0.00500 mol CO"_2 xx ("1 mol O"_2)/("1 mol CO"_2) xx (6.022 xx10^23 " molecules O"_2)/("1 mol O"_2)=0.00500 mol CO2×1 mol O21 mol CO2×6.022×1023 molecules O21 mol O2

= 3.01 xx 10^21" molecules O"_2=3.01×1021 molecules O2