An unknown element #"X"# has electron configuration #["Ar"]3d^5# and a charge of #3+#. What is the atomic number of #"X"#?
1 Answer
Explanation:
For starters, you know that your element is located in period
This means that you can write the noble-gas shorthand configuration for this unknown element, let's say
#"X"^(3+): ["Ar"] 3d^5#
Now, the trick here is to realize that when a transition metal located in period
In other words, when the
So when
You can thus backtrack and add electrons to the
#"X"^(2+) = "X"^(3+) + "e"^(-)#
This means that you have--remember, the third electron was removed from the
#"X"^(2+): ["Ar"] 3d^6#
Next, you have
#"X" = "X"^(2+) + 2"e"^(-)#
This means that you have--the first two electrons were removed from the
#"X": ["Ar"]3d^6 4s^2#
Therefore, you can say that a neutral atom of
#overbrace("18 e"^(-))^(color(blue)("the same as neutral atom of Ar")) + overbrace("6 e"^(-))^(color(blue)("in the 3d orbitals")) + overbrace("2 e"^(-))^(color(blue)("in the 4s orbitals")) = "26 e"^(-)#
This implies that a neutral atom of
You can conclude that your unknown element is iron,