How many moles of water are produced when $2.15 moles$ $"2.15 moles"$ of oxygen gas react with excess hydrogen gas?

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How many moles of water are produced when $2.15 moles$ $"2.15 moles"$ of oxygen gas react with excess hydrogen gas?

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Answer 1 · 2017-10-23T05:41:16

$4.30 moles$ $"4.30 moles"$

Explanation:

$I mol$ $"I mol"$ of $O_{2}$ $"O"_2$ produces $2 moles$ $"2 moles"$ of $H_{2} O$ $"H"_2"O"$ , so $2.15 moles$ $"2.15 moles"$ of $O_{2}$ $"O"_2$ produce

$\frac{2}{1} \times 2.15 = {4.30 moles H}_{2} O$ $2/1×2.15 = "4.30 moles H"_2"O"$

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How many moles of water are produced when $2.15 moles$ $"2.15 moles"$ of oxygen gas react with excess hydrogen gas?

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How many moles of water are produced when 2.15 moles"2.15 moles" of oxygen gas react with excess hydrogen gas?

1 Answer

Explanation:

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How many moles of water are produced when $2.15 moles$ $"2.15 moles"$ of oxygen gas react with excess hydrogen gas?