Question #51f38

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Answer 1 · 2017-10-29T19:45:48

There are approximately $2.38$ moles of sodium bicarbonate in $"200 g"$ .

We must first find the molar mass of sodium bicarbonate, $"NaHCO"_3$ .

We do this as follows:

1) Find the molar mass of each element in the compound.

$"Na = 22.99 g/mol"$

$"H = 1.008 g/mol"$

$"C = 12.01 g/mol"$

$"O = 16.00 g/mol"$

2) Add up the molar masses to find the molar mass of the compound.

$1(22.99) + 1(1.008) + 1(12.01) + 3(16.00) = "84.008 g/mol"$

This means that each mole of sodium bicarbonate weighs about $84.008$ grams.

3) Divide the number of grams by the molar mass to find moles.

$"200 g"/"84.008 g/mol" = "2.38 moles"$

Note: Keep in mind that you have one significant figure for the mass of sodium bicarbonate!