Question #8da6a

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Question #8da6a

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Answer 1 · 2017-11-24T00:02:51

$N_{A}$ $N_"A"$

Explanation:

I'm not sure if this is what you wanted to ask, but the answer here is Avogadro's constant.

The idea is that in order to have $1$ $1$ mole of atoms of neon in a given sample, you need to have $6.022 \cdot 10^{23}$ $6.022 * 10^(23)$ atoms of neon. This is known as Avogadro's constant, $N_{A}$ $N_"A"$ , and is how a mole is defined.

Since you have

$1 mole Ne = 6.022 \cdot 10^{23} . atoms Ne - ---------------------------- -$ $color(blue)(ul(color(black)("1 mole Ne" = 6.022 * 10^(23)color(white)(.)"atoms Ne")))$

and

$6.022 \cdot 10^{23} . atoms Ne = N_{A} . atoms Ne - ------------------------------- -$ $color(blue)(ul(color(black)(6.022 * 10^(23)color(white)(.)"atoms Ne" = N_"A" color(white)(.)"atoms Ne")))$

you can say that $1$ $1$ mole of neon contains $N_{A}$ $N_"A"$ atoms of neon.

$1 mole Ne = N_{A} . atoms Ne$ $"1 mole Ne" = N_"A" color(white)(.)"atoms Ne"$

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Question #8da6a

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