Question #e7817
1 Answer
Explanation:
Your unknown compound has
#7# moles of carbon,#7 xx "C"# #8# moles of hydrogen,#8 xx "H"# #x# moles of oxygen,#x xx "O"#
This means that the molar mass of the compound can be calculated like this
#M_"M" = overbrace(7 xx "12.011 g mol"^(-1))^(color(blue)("7 moles C")) + overbrace(8 xx "1.00794 g mol"^(-1))^(color(blue)("8 moles H")) + overbrace(x xx "15.9994 g mol"^(-1))^(color(blue)(x quad "moles O"))#
#M_"M" = (94.14052 + 15.9994 * x)quad "g mol"^(-1)#
Now, you know that this compound contains
#( 15.9994 * x color(red)(cancel(color(black)("g mol"^(-1)))))/((94.14052 + 15.9994 * x)color(red)(cancel(color(black)("g mol"^(-1))))) xx 100% = 26.2%# This basically means that if you take the mass of oxygen present in
#1# mole of this compound, divide it by the total mass of#1# mole of the compound, and multiply the result by#100%# , you will end up with#26.2%# , the percent concentration by mass of oxygen.
You will thus have
# (15.9994 * x)/((94.14052 + 15.9994 * x)) xx 100 color(red)(cancel(color(black)(%))) = 26.2color(red)(cancel(color(black)(%)))#
Rearrange to solve for
#15.9994 * 100 * x = 26.2 * 94.14052 + 26.2 * 15.9994 * x#
#x * 15.9994 * (100 - 26.2) = 26.2 * 94.14052#
You will end up with
#x = (26.2 * 94.14052)/(15.9994 * (100 - 26.2)) = 2.089 ~~ 2#
You can thus say that you have