Question #6018c

2 Answers
Dec 12, 2017

356 - 293 = 63 , or "6 tens and 3 ones".

49 xx 10 + 82 xx 1 - (12 xx 10 + 96 xx 1) - (6 xx 10 + 3 xx 1) = 293

Explanation:

Using the place descriptions, the equation is:

49 xx 10 + 82 xx 1 - (12 xx 10 + 96 xx 1) = 293

490 + 82 - (120 + 96) = 293
572 - 216 = 293
356 = 293 SO the "missing factor" on the other side must be

356 - 293 = 63 , or "6 tens and 3 ones".

49 xx 10 + 82 xx 1 - (12 xx 10 + 96 xx 1) - (6 xx 10 + 3 xx 1) = 293

Dec 12, 2017

The value of x is 63
You can express this amount as "6 tens 3 ones."

Explanation:

I think the question has a typo where the x's didn't show up.

I think the question should be:
If 49 tens 82 ones - 12 tens 96 ones = x + 293, then find the value of x

This question implies that "293" is too small, and it wants to know how much you'd need to add to make the answer correct.

Here is a good way to solve this problem.

1) For your own convenience, turn the bills into a sum of money.

49 tens  = $490
82 ones = $   82
......................................
Total . . . . . $572

12 tens  = $120
96 ones = $   96
.....................................
Total. . . . . .$216

Now you can write the question like this:
[49 tens 82 ones] - [12 tens 96 ones] = x + 293
[ . . . . . 572 . . . . . ] - [ . . . . . 216 . . . . . ] = x + 293

572 - 216 = x + 293
Solve for x

1) Combine like terms by doing the subtraction
356 = x + 293

2) Subtract 293 from both sides to isolate x
63 = x larr answer

Answer:
The value of x is 63

Check:
572 - 216 . . = . . . 63 + 293?
. . . . 356 . . . . .= . . . . .356
Check!