Question #4c11e

2 Answers
Jan 10, 2018

1.28g1.28g of isocane.

Explanation:

C_20H_42C20H42 is called isocane.

It has a molar mass of 282.5475g"/"mol282.5475g/mol.

This means, in 4.52*10^-34.52103 moles of isocane, there is

282.5475g*4.52*10^-3=1.28g282.5475g4.52103=1.28g of isocane.

Jan 10, 2018

"1.28 g"1.28 g

Explanation:

Calculate the molar mass of "C"_20"H"_42C20H42 by taking

20xx("molar mass C") + 42xx("molar mass H")20×(molar mass C)+42×(molar mass H)

This gives

20xx"12.011 g/mol" + 42xx"1.0079 g/mol" = "282.5518 g/mol"20×12.011 g/mol+42×1.0079 g/mol=282.5518 g/mol

Now, take the molar mass and multiply it by the number of moles.

("282.5518 g/mol") xx (4.52 * 10^-3 quad "moles")= "1.277134 g"

Rounded to three sig figs, this is "1.28 g".