"mol of Mg" = "4.9 g" /"24 g/mol" = "0.2 mol"mol of Mg=4.9 g24 g/mol=0.2 mol
"mol of O" = "3.2 g"/"16 g/mol" = "0.2 mol"mol of O=3.2 g16 g/mol=0.2 mol
So the mole ratio is
0.2: 0.2 = 1:10.2:0.2=1:1
Therefore, "Mg"_1"O"_1 = "MgO"Mg1O1=MgO is the empirical formula.