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Answer 1 · 2018-02-12T03:54:04

$0.05$ $0.05$ moles of $N_{2} H_{6} C O_{2}$ $N_2H_6CO_2$

Well, we would first need to calculate the molar mass of $N_{2} H_{6} C O_{2}$ $N_2H_6CO_2$ .

$N$ $N$ has a molar mass of $14 g / m o l$ $14g"/"mol$ .

$:.N_2$ has a molar mass of $28g"/"mol$ .

$H$ has a molar mass of $1g"/"mol$ .

$:.H_6$ has a molar mass of $6g"/"mol$ .

$CO_2$ has a molar mass of $44g"/"mol$ .

$:.N_2H_6CO_2$ has a molar mass of $28+6+44=78g"/"mol$ .

$"moles"="mass"/"molar mass"$

$:."moles"=(4cancelg)/(78cancelg"/"mol)=0.05mol$