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Answer 1 · 2018-02-11T03:35:28

Molarity $=$ (Number of moles of Solute)/(Volume of Solution in Litre)

Here Solute is $NaCl$ (s) and solution is the $NaCl$ (aq)

So, here we have to make $1 Litre$ of $4M$ $NaCl$ solution.

$rArr$ Molarity of $NaCl$ solution $=$ $4M$

and,

Volume of the $NaCl$ solution $=$ $1 L$

The Molar mass of $NaCl$ = $58.44$ g/mol

Using the formula of Molarity here we get :-

Molarity of $NaCl$ solution $=$ (Number of moles of $NaCl$ )
/ (Volume of the $NaCl$ solution in Litre)

$rArr$ $4M$ $=$ (Number of moles of $NaCl$ )/ $1L$

$rArr$ $4M$ x $1L$ $=$ Number of moles of $NaCl$

$:.$ Number of moles of $NaCl$ $=$ $4$ moles

Amount of $NaCl$ needed $=$ $4$ moles x $58.44$ g/mol

$rArr$ Amount of $NaCl$ needed $=233.76$ g $=0.233$ kg