Question #73ed2

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Question #73ed2

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Answer 1 · 2018-02-12T04:56:15

The answer is undefined.

Explanation:

Some people might say that the answer is $\frac{25}{24}$ $25/24$ , and technically, they aren't wrong, because:

$f (f^{- 1} (x)) = x$ $f(f^-1(x))=x$

and in this case:

$sin ({sin}^{- 1} (\frac{25}{24})) = \frac{25}{24}$ $sin(sin^-1(25/24))=25/24$

But this actually isn't true. If you try to simplify the problem, you'll find that the domain of ${sin}^{- 1} x$ $sin^-1x$ is [ $- 1$ $-1$ , $1$ $1$ ], and $\frac{25}{24}$ $25/24$ is outside of that (basically, ${sin}^{- 1}$ $sin^-1$ literally can't take in numbers bigger than $1$ $1$ or smaller than $- 1$ $-1$ ).

Therefore, it cannot be simplified further.

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Question #73ed2

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