A 7.3 kg bowling ball and a 8.1 kg bowling ball rest on a rack 1.27 m apart. What is the force of gravity exerted on each of the balls by the other ball?

1 Answer
Stuart W.
Nov 11, 2015

7.3Kg Ball on 8.1Kg Ball = #2.44*10^-9 N#
8.1Kg Ball on 7.3Kg Ball = #2.44*10^-9 N#

Explanation:

To calculate the answers to this question you need the Universal Gravitation Formula:

#F = G*(m_1*m_2)/r^2#

#G=6.67*10^-11 N*m^2/(Kg^2)#

Because each ball will exert an equal force on the other, it is not necessary to distinguish between them in terms of their magnitude. When you plug in your values you get:

#F=(6.67*10^-11)*(8.1*7.3)/(1.27)^2#

#F=2.44*10^-9N#

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