A balanced lever has two weights on it, the first with mass #1 kg # and the second with mass #4 kg#. If the first weight is # 25 m# from the fulcrum, how far is the second weight from the fulcrum?

Question

1180 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-08T14:28:23

#6.25 \ "m"#

For a balanced lever, we have the following relationship:

#m_1d_1=m_2d_2#

#m_1,m_2# are the masses of the two objects

#d_1,d_2# are distances of the two objects from the fulcrum

And so,

#1 \ "kg"*25 \ "m"=4 \ "kg"*d_2#

#d_2=(1color(red)cancelcolor(black)"kg"*25 \ "m")/(4color(red)cancelcolor(black)"kg")#

#=6.25 \ "m"#