A balanced lever has two weights on it, the first with mass #15 kg # and the second with mass #9 kg#. If the first weight is # 4 m# from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-12-09T14:49:34

The distance is #=6.67m#

The moments on both sides of the fulcrum must de equal on equilibrium.

#Moment =#Force x distance

So,

Moment of first weight #=15g*4=60g Nm#

Moment of the second weight #=9g*d Nm#

Where #d=# distance from the fulcum

On equilibrium

#60g=9g*d#

#d=60/9=20/3=6.67m#