A ball with a mass of #480 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #24 (kg)/s^2# and was compressed by #8/5 m# when the ball was released. How high will the ball go?

Question

1162 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-11T07:59:01

The height is #=6.53m#

enter image source here

The spring constant is #k=24kgs^-2#

The compression is #x=8/5m#

The potential energy in the spring is

#PE=1/2*24*(8/5)^2=30.72J#

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

#KE_(ball)=1/2m u^2#

Let the height of the ball be #=h #

Then ,

The potential energy of the ball is #PE_(ball)=mgh#

#PE_(ball)=30.72=0.48*9.8*h#

#h=30.72*1/(0.48*9.8)#

#=6.53m#