Question

A balloon filled with oxygen gas occupies a volume of 5.5 L at 25°C. What volume will the gas occupy at 100.0 °C?

Answer 1

`V_2=6.9L`

Explanation:

To answer this question, we will need to assume the following:

1. Oxygen is behaving ideally, so we can use the ideal gas law: `PV=nRT`
2. During the process, the pressure is remaining constant.

Since we are heating the ballon, the number of mole is not changing and therefore, `n` is constant too.

Thus `V=underbrace((nR)/P)_(color(blue)("constant k"))T=>V/T=k=>(V_1)/(T_1)=(V_2)/(T_2)`

`=>V_2=(V_1)/(T_1)xxT_2=(5.5L)/(298cancel(K))xx373cancel(K)=6.9L`

Therefore, oxygen will occupy a volume of `6.9L` at `100^@C`.