Question

A balloon that contains 1.50 L of air at 1.00 atm is taken underwater to a depth at which the pressure is 3.00 atm. What the new volume of the balloon, assuming constant temperature?

Answer 1

At constant `T`, we use Boyle's Law. . Volume should decrease proportionally at treble the pressure.

Explanation:

`P_1V_1=P_2V_2`

`V_2=(P_1V_1)/P_2` `=` `(1.00*atmxx1.50*L)/(3.00*atm)` `=` `0.500*L`