A beam of light passes from quartz to zircon at an angle of 19°. What is the angle of refraction? What is the critical angle when passing from zircon to quartz?

1 Answer
Jun 3, 2016

#r=14.88 ^o#

#theta_C=51.98" "^o#

Explanation:

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#"assuming "n_q=1.544 " , " " n_z=1.960 " ,"sin 19=0.326 #

#"using Snell law:"#

#n_q*sin i=n_z*sin r#

#1.544*sin 19=1.960* sin r#

#1.544*0.326=1.960*sin r#

#0.503344=1.960*sin r#

#sin r=(0.503344)/(1.960)#

#r=14.88 ^o#

#"critical angle for light passing from zircon to quartz:"#

#theta_C=" critical angle"#

#sin theta_C*n_z=sin 90*n_q#

#so; sin 90=1#

#sin theta_C*n_z=1*n_q#

#sin theta_C=n_q/n_z=(1.544)/(1.960)#

#theta_C=51.98" "^o#