A charge of #12 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #54 J# to #36 J#, what is the voltage between points A and B?

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Answer 1 · 2017-03-29T06:42:10

The voltage is #=1.5V#

The potential difference between the points #A# and #B# is #=U#

Voltage =Energy/Charge

#U=(DeltaE)/Q#

#DeltaE=54-36=18J#

The charge is #Q=12C#

#1 V=(1J)/C#

#U=18/12=1.5V#

Answer 2 · 2017-03-29T06:43:01

#-1.5V#

#E=V*Q#
#36-54=V*12#
#V=-18/12=-1.5V#