A charge of 16 C is passing through points A and B on a circuit. If the charge's electric potential changes from 48 J to 12 J, what is the voltage between points A and B?

1 Answer
Apr 14, 2016

V_"AB"=-2,25 V

Explanation:

q=16C
E_A=48 J" the electric potential energy at the point of A"

E_B=12J" the electric potential energy at the point of B"

E_B-E_A=12-48=-36J" work between the A and B"

W=q*V_"AB"

-36=16*V_"AB"

V_"AB"=-36/16

V_"AB"=-2,25 V