A charge of #16 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #32 J# to #6 J#, what is the voltage between points A and B?

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Answer 1 · 2017-07-19T05:54:32

The voltage is #=1.625V#

The charge is #Q=16C#

The change in the electric potential is

#DeltaE=32-6=26J#

The power is

#P=UI#

and the energy is

#E=UIt#

Also,

#Q=It#

Therefore,

#DeltaE=U*Q#

The voltage is

#U=DeltaE/Q=26/16=1.625V#