A charge of $16 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $32 J$ to $6 J$ , what is the voltage between points A and B?

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Answer 1 · 2017-07-19T05:54:32

The voltage is $=1.625V$

The charge is $Q=16C$

The change in the electric potential is

$DeltaE=32-6=26J$

The power is

$P=UI$

and the energy is

$E=UIt$

Also,

$Q=It$

Therefore,

$DeltaE=U*Q$

The voltage is

$U=DeltaE/Q=26/16=1.625V$

A charge of 16 C16 C is passing through points A and B on a circuit. If the charge's electric potential changes from 32 J32 J to 6 J6 J, what is the voltage between points A and B?