A charge of #16 C# passes through a circuit every #12 s#. If the circuit can generate #9 W# of power, what is the circuit's resistance?

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Answer 1 · 2017-11-03T15:07:57

I got #5Omega#

We can evaluate current as:

#I=Q/t# i.e. the charge that passes in time.

With your data:

#I=16/12=1.3A#

Now, power is:

#P=VI# that using Ohm's Law #V=RI# can be written as:

#P=RI^2#

rearranging:

#R=P/I^2=9/1.3^2=5Omega#