A charge of $2 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $28 J$ to $19 J$ , what is the voltage between points A and B?

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Answer 1 · 2016-06-04T09:45:12

$V_"AB"=-4.5" "V$

$Delta W=19-28=-9J$

$Delta W=q(V_B-V_A)" ; "V_B-V_A=V_"AB"$

$Delta W=q*V_"AB"$

$V_"AB"=(Delta W)/q$

$V_"AB"=-9/2$

$V_"AB"=-4.5" "V$

A charge of 2 C2 C is passing through points A and B on a circuit. If the charge's electric potential changes from 28 J28 J to 19 J19 J, what is the voltage between points A and B?