A charge of 2 C is passing through points A and B on a circuit. If the charge's electric potential changes from 25 J to 14 J, what is the voltage between points A and B?

1 Answer
Feb 13, 2018

5.5"V"

Explanation:

The relationship between the change in electric potential and the voltage and charge between two points is:

W=qV, where:

W is the change in potential energy, or the work done.

q is the charge passing through the points

V is the difference in voltage.

Rearranging the equation to solve for V, we get:

V=W/q.

Here, W=25"J"-14"J"=11"J", and q=2"C".

Inputting these values, we get:

V=11/2

V=5.5 volts.