Question

A charge of `24` `C` passes through a circuit every `4` `s`. If the circuit can generate `48` `W` of power, what is the circuit's resistance?

Answer 1

The resistance of the circuit is `1.33` `Omega`.

Explanation:

The current in a circuit is the rate of flow of charge:

`I=(Delta Q)/t=(24C)/(4s)=6` `A`

The power of an electric circuit is given by `P=I^2R`.

Rearranging:

`R=P/I^2=(48W)/(6^2A^2)~~1.3` `Omega`