A charge of 4 C is passing through points A and B on a circuit. If the charge's electric potential changes from 27 J to 11 J, what is the voltage between points A and B?

1 Answer

DeltaV=-4" "volts

Explanation:

The formula for the Difference in Electric Potential in volts

#DeltaV=V_B-V_A=(EPE_B-EPE_A)/q_0

Where V_B=Electric potential at point B
V_A=Electric potential at point A

Electric Potential Energy final
EPE_B=11" "Joule

Electric Potential Energy initial
EPE_A=27" "Joule

Test charge
q_0=4" "Coulomb

DeltaV=V_B-V_A=(EPE_B-EPE_A)/q_0=(11-27)/4=-4" "volts