A charge of 4 C4C is passing through points A and B on a circuit. If the charge's electric potential changes from 27 J27J to 15 J15J, what is the voltage between points A and B?

1 Answer
Jul 5, 2018

33 volts

Explanation:

Using the definition, voltage is the difference of electric potential between two points per unit charge passing through it. We can express it as an equation in the form of:

V=(B-A)/CV=BAC

where:

  • BB is the electric potential of the second point

  • AA is the electric potential of the first point

  • CC is the charge passing through in coulombs

So, we get:

V=(27 \ "J"-15 \ "J")/(4 \ "C")

=(12 \ "J")/(4 \ "C")

=3 \ "V"