A charge of $4 C$ $4 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ $27 J$ to $18 J$ $18 J$ , what is the voltage between points A and B?

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A charge of $4 C$ $4 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ $27 J$ to $18 J$ $18 J$ , what is the voltage between points A and B?

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Answer 1 · 2016-02-01T12:42:41

$\frac{9}{4} V$ $9/4V$

Explanation:

Voltage is just another name for electrical potential difference - that is, the change in electric potential between two points per coulomb.

$1 V = 1 \frac{J}{C}$ $1V = 1 J/C$

If the $4 C$ $4C$ charge's electric potential drops from $27 J$ $27J$ to $18 J$ $18J$ then the voltage is
$V = \frac{27 - 18}{4} = \frac{9}{4} V$ $V = (27-18)/4 = 9/4 V$

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A charge of $4 C$ $4 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ $27 J$ to $18 J$ $18 J$ , what is the voltage between points A and B?

1 Answer

Explanation:

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A charge of 4 C4C4 C is passing through points A and B on a circuit. If the charge's electric potential changes from 27 J27J27 J to 18 J18J18 J, what is the voltage between points A and B?

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Explanation:

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A charge of $4 C$ $4 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ $27 J$ to $18 J$ $18 J$ , what is the voltage between points A and B?