A charge of $4$ $4$ $C$ $C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $45$ $45$ $J$ $J$ to $18$ $18$ $J$ $J$ , what is the voltage between points A and B?

Question

1464 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-26T22:09:19

We have $V = q E$ $V=qE$ or, better, $Delta V = qDelta E$ .

So $Delta V = 4* (18-45)=-108$ $V$

The voltage difference between the points is $108$ $V$

The negative sign shows that A is at a lower voltage than B, which makes sense because the electric potential energy is lower at B than at A.

A charge of 444 CCC is passing through points A and B on a circuit. If the charge's electric potential changes from 454545 JJJ to 181818 JJJ, what is the voltage between points A and B?