A charge of $4 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $25 J$ to $15 J$ , what is the voltage between points A and B?

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Answer 1 · 2017-09-04T16:30:02

The voltage is $=2.5V$

The charge is $Q=It$

We apply Ohm's Law

$U=RI$

The power is

$P=UI$

And the energy is

$E=UIt$

$E=UQ$

and

$DeltaE=QDeltaU$

The voltage is

$DeltaU=(DeltaE)/Q=(25-15)/4=10/4=2.5V$

A charge of 4 C4 C is passing through points A and B on a circuit. If the charge's electric potential changes from 25 J25 J to 15 J15 J, what is the voltage between points A and B?