Question

A charge of `40 C` passes through a circuit every `8 s`. If the circuit can generate `45 W` of power, what is the circuit's resistance?

Answer 1

I found `1.8Omega`

Explanation:

We can get the current `I` considering that:
`I=q/t=40/8=5A`
Now we use the power `P` to write its expression involving current and resistance as:
`P=I^2R`
that rearranged lead us to:
`R=P/I^2=45/5^2=45/25=1.8Omega`