A charge of $5 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $27 J$ to $18 J$ , what is the voltage between points A and B?

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Answer 1 · 2017-08-15T06:13:41

The voltage is $=1.8V$

The charge is $Q=It$

We apply Ohm's Law

$U=RI$

The power is

$P=UI$

And the energy is

$E=UIt$

$E=UQ$

and

$DeltaE=QDeltaU$

The voltage is

$DeltaU=(DeltaE)/Q=(27-18)/5=9/5=1.8V$

A charge of 5 C5 C is passing through points A and B on a circuit. If the charge's electric potential changes from 27 J27 J to 18 J18 J, what is the voltage between points A and B?